How can I remove (set to NaN) values in matrix starting at row index value and all following values which differ for each column

I have two matrices (kz and zdr) of equal size [997 x 359]. I want to find the first value for each column in zdr>3.5 and use the index to set kz=NaN, but I want all following rows to be equal to NaN as well regardless of their value in zdr.

example: a=-4; b=5; zdr=(b-a).*rand(959,359) + a; kz=randn(997,358);

[mie_rows,mie_cols]=find(zdr>3.5) mie=[mie_rows,mie_cols];

so in my case the first column [23,1] is the first row beyond 3.5. I would therefore like kz from row 23 and beyond to be NaN, the next column is [1,2], from row 1 and beyond of kz is NaN, and etc...

[Amir]

Please try this code. I hope it works for you

a=-4; b=5; zdr=(b-a).*rand(959,359) + a; kz=randn(997,359); for i=1:size(zdr,2) kz(min(find(zdr(:,i)>3.5))+1:end,i)=NaN; end

Answer 1

[Amir]

Please try this code. I hope it works for you

a=-4; b=5; zdr=(b-a).*rand(959,359) + a; kz=randn(997,359);
for i=1:size(zdr,2)
    kz(min(find(zdr(:,i)>3.5))+1:end,i)=NaN;
end

[Brandon]

Thanks for the help works perfectly

[Brandon]

one quick edit, the +1 keeps the first value of >3.5, when I didnt want that. Guess I wasnt to clear. Removing the +1 works fine though.