i f i have an array a=[1 2 3 4 1;6 7 8 9 2].I need to split this array based on the value in last column.Resultant array b=[1 2 3 4],c=[6 7 8 9]. The splitted array b should contain the row whose last column is 1 and c 2

a=[1 2 3 4 1 5 6 7 8 2 3 4 5 6 1 4 3 2 1 1] Resultant matrix is : b=[1 2 3 4 3 4 5 6 4 3 2 1] c=[5 6 7 8]

Answer 1

[Julia]

Hi,

here is a solution for your small problem. If a is larger, you can use a loop.

b=[];
c=[];

if a(1,end)==1
b=[b,a(1,1:end-1)];
end
if a(2,end)==2
c=[c,a(2,1:end-1)];
end

Or with switch-case. Something like:

switch a(i,end) % where i is a counting index of a loop
  case 1
   b=[b,a(i,1:end-1)];
  case 2
   c=[c,a(i,1:end-1)];
end