am using this code to generate binary matrix dec2bin(rand(50,1)*2^32) but i need to add one space between the matrix element so i can use it for other commands. the output matrix needs space to be useful for other calculation. how to do this?

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Guillaume
Guillaume le 9 Nov 2014
Modifié(e) : Guillaume le 9 Nov 2014
The following would work:
m = dec2bin(rand(50,1)*2^32)
mwithspaces = cell2mat(regexprep(num2cell(m, 2),'\d(?=\d)', '$0 '));
I have to ask though, why do you want to do that? It seems like an unnecessary step. I would think that any algorithm that follows is probably going to remove these spaces one way or another.
edit: was missing a bracket

5 commentaires

Image Analyst
Image Analyst le 9 Nov 2014
It gives a 2D character array, not a simple string. I think maybe he wants all those rows concatenated together with a space in between them.
In that case:
mwithspaces = regexprep(reshape(m', 1, []), '\d(?=\d)', '$0 '));
or
strjoin(num2cell(reshape(m', 1, [])), ' ');
But I still think that not doing this and changing the steps that follow to not require the spaces is probably a better idea.
Image Analyst
Image Analyst le 9 Nov 2014
I agree with you there.
As commented on Jan's answer, inserting spaces is a red herring. To convert a string of zeros and ones into a matrix of zeros and ones numbers, simply subtract '0' from the string.
This may be what you're looking for:
M = dec2bin(rand(10, 1) * 2^32);
M = M - '0'; %convert M into an array of numbers 0 or 1
[m, n] = size(M);
M2 = [zeros(m, 3*ceil(n/3)-n), M];
X = xor(xor(M2(:, 1:3:end-2), M2(:, 2:3:end-1)), M2(:, 3:3:end))
janny
janny le 10 Nov 2014
it works fine... thanks a lot....

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Plus de réponses (2)

Jan
Jan le 9 Nov 2014
Modifié(e) : Jan le 9 Nov 2014
s = dec2bin(rand(50,1)*2^32);
t = repmat(' ', size(s, 1), size(s, 2) * 2 - 1);
t(:, 1:2:end) = s;

2 commentaires

janny
janny le 9 Nov 2014
Modifié(e) : janny le 9 Nov 2014
i'm writing an algorithm to calculate CA rule 150 from this sequence, so when i try these codes didn't give the right answer, this is my code:
M = dec2bin(rand(10,1)*2^32);
[m,n] = size(t);
M2 = [zeros(m,3*ceil(n/3)-n),t];
X = xor(xor(M2(:,1:3:end-2),M2(:,2:3:end-1)),M2(:,3:3:end))
if : M = [0 0 0 1 1 1 1 1 1 0 1 1 1 0 1 0 0 0 0 0 0 1 1 0 1 0 0 1 0 1 1 1]
then X = 0 0 1 0 0 1 0 0 1 1 1
so how to make it run?
Guillaume
Guillaume le 9 Nov 2014
Modifié(e) : Guillaume le 9 Nov 2014
I don't know what CA rule 150 is so why don't you explain it.
It is now clear however, that your original question is a case of xy problem. Looking at your attempted code, you don't need to insert spaces and actually want to operate on numbers rather than strings.
xor certainly does not work with strings.
See comment on my own answer for a possible solution.

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yonatan gerufi
yonatan gerufi le 9 Nov 2014

0 votes

see in the "file exchange" :

3 commentaires

janny
janny le 9 Nov 2014
it did not run for this issue.if i have matrix as (1110) i want to add one space between the element of it (1 1 1 0) so i want to modify this code if its possible
dec2bin(rand(50,1)*2^32)
so it can add the space automatically.
yonatan gerufi
yonatan gerufi le 9 Nov 2014
perhaps i misunderstood you.
the code : dec2bin(rand(50,1)*2^32)
gives you string of ones & zeros. you can pad it with ' ' (space), and then you will have space between the elements.
Image Analyst
Image Analyst le 9 Nov 2014
It gives a 2D character array, not a simple string. I think maybe he wants all those rows concatenated together with a space in between them.

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