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Random pulse generator

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Néstor Monedero
Néstor Monedero le 19 Oct 2011
Commenté : sneha j le 3 Mai 2021
Hello,
I'm new in Simulink and i trying to make a pulse random generator. Pulses have amplitude (+10 & -10) and width (1 ms). The signal has to be non periodic, i mean, pulses has to appear by a random series. how can i do it? I apprecitate any help. The begining of my project depend of this signal.
Thanks. Néstor.
  3 commentaires
Néstor Monedero
Néstor Monedero le 29 Oct 2012
Hi Azzi, The maximale distance between two impulses may be 2 ms, for example. The idea is that: the distance is as close as possible. I achieve to do this pulse random generator with these blocks: A uniform random number, a matlab function that convert this pulses in other with amplitude +1/-1.
If you need more information, please, give me question. Néstor
Azzi Abdelmalek
Azzi Abdelmalek le 29 Oct 2012
Check the second image (modified)
set the Amplitude of the pulse generator to 2 and substract 1

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Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 27 Oct 2012
Modifié(e) : Azzi Abdelmalek le 27 Oct 2012
use this block
the function is
function y = fcn(u)
%#codegen
id=rand(1)
if id>0.5 & u==0
y=1
else
y=0
end
or easier
%

Plus de réponses (2)

Fangjun Jiang
Fangjun Jiang le 19 Oct 2011
Go to Simulink Sources library, there is the Random Number block and the Uniform Random Number block.
The output of the Uniform Random Number is between 0 and 1, so you'll need to use Relational Operator block to compare it with constant such as 0.1 and 0.9, and then use Switch block to output the +10 or -10 or 0 pulse value.
  3 commentaires
Fangjun Jiang
Fangjun Jiang le 21 Oct 2011
You can compare the random number with a constant, e.g. 0.9 and then add a zero-order holder block.
Fangjun Jiang
Fangjun Jiang le 28 Nov 2011
See update.

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Néstor Monedero
Néstor Monedero le 28 Nov 2011
I try to simulate random pulse generator using "uniform random number" plus a Matlab function. The code of the Matlab function is:
function y = fcn(u)
%#codegen
n=length(u);
y=[1:n];
for i=1:n
if(u(i)<-0.9)
y(i)=-1;
end
if(u(i)>0.9)
y(i)=1;
else
y(i)=0;
end
end
The result is not what i want. I only obtain pulses with positive amplitude. I need two kind of pulses: positive and negative. what i am doing wrong? any idea? Please i need to build this signal to advanced in my project. Thanks in advance. Néstor.
  2 commentaires
sneha j
sneha j le 3 Mai 2021
hi, there is a bug in ur code.
In the case that u(i)<-0.9, y(i) sets to -1 in the first if-block.
But wen it executes the 2nd if-block - if gets overwritten by y(i)=0 as u(i)<0.9, so it executes the else part of the block.
U need to club the the first if block with the 2nd if-else block into one if block as follows:
if(u(i)<-0.9)
y(i)=-1;
else if(u(i)>0.9)
y(i)=1;
else
y(i)=0;
end
Hope it works well.
sneha j
sneha j le 3 Mai 2021
hi Nestor, sorry i jus realised that the else if block doesnt work, so here is a workaround:
if(u<-0.5)
y=-10;
else
y=0;
end
if(u>0.5)
y=10;
end

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