Count amount of 0's and 1's in an array

Hello, I'm working on a image processing project. My current task is to get the number of 0's and 1's connected elements. Example: I have an 1D array which looks like:

[0000 1111 0000000 1111 000 1 00 11111 00 11111 00]

What I want is to count elements connected to each other and return something like this:

[4 4 7 4 3 1 2 5 2 5 2]

Is there any easy way to do that? This includes generating dynamical array, so I have no idea how to do that without iterating through array twice

Answer 1

[Mahdiyar]

Hi Melov

Please, let me know if it is what you want.

clc
clear 
A = [0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 1 1 1 1 0 0 0 1 0 0 1 1 1 1 1 0 0 1 1 1 1 1 0 0];

B = A(2:end);

C = A(1:end-1) - B;
D = find(C~=0);
Result = [D(1) D(2:end) - D(1:end-1) length(A)-D(end)]

Regards,

[Sasha Melov]

works exactly like I wanted,thank you!

Answer 2

[Jan]

See FEX: RunLength

A = [0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 1 1 1 1 0 0 0 1 0 0 1 1 1 1 1 0 0 1 1 1 1 1 0 0];
[B, N] = RunLength(A);

B =
   0     1     0     1     0     1     0     1     0     1     0
N =
   4     4     7     4     3     1     2     5     2     5     2

Answer 3

[Jos (10584)]

Since the array is always an alternation of zeros and ones

N = diff([0 find(diff(A)) numel(A)])

will produce the runs of consecutive zeros and ones.