I don't understand what is the problem.....i tried it, but get an error. So plz help me to solve the problem...
2 vues (au cours des 30 derniers jours)
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"Write a function called integerize that takes as its input a matrix A of non-negative integers of type double, and returns the name of the “smallest” unsigned integer class to which A can be accurately converted. If no such class exists, the string 'NONE' is returned. For example, if the largest integer A is 14, then the function would return 'uint8', but if the largest integer in A is 1e20, then the function would return 'NONE'."
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Réponses (5)
Image Analyst
le 30 Mai 2015
Hint: see functions intmax() and max()
mavValue = max(A(:))
if maxValue < intmax('uint8')
and so on...
3 commentaires
Muhammad Usman Saleem
le 1 Juin 2015
@image in another approach i use..
function integ=integerize(A)
if int(A) && uint(A)
if max(A)<=intmax('uint16')
integ='uint16';
elseif max(A) <= intmax('uint32')
integ='uint32';
elseif max(A) <= intmax('uint64')
integ='uint64';
elseif mod(A,1)=>0
integ='NONE';
end
end
end
but the error remains same as mentioned above..
Image Analyst
le 1 Juin 2015
Muhammad, It looks like you've gotten your own thread started in this other thread so we'll just have the discussion over there.
Mostafa Farhoudi
le 15 Juil 2015
Modifié(e) : Walter Roberson
le 16 Juil 2015
function integ=integerize(A)
integ = 'none';
maxValue=max(A(:));
disp(maxValue);
if maxValue <= intmax('uint8')
integ='uint8';
elseif maxValue<=intmax('uint16')
integ='uint16';
elseif maxValue <= intmax('uint32')
integ='uint32';
elseif maxValue <= intmax('uint64')
integ='uint64';
else
integ='NONE';
end
end
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Pranash Azrot
le 25 Août 2015
yaar mera answer teek see.
function u = integerize(A)
g =max(max(A));
if (g>255 && g<=intmax('uint16'))
u = 'uint16';
elseif (g<0 || g>intmax('uint64'))
u = 'NONE';
elseif (g>intmax('uint16') && g<=intmax('uint32'))
u = 'uint32';
elseif (g>intmax('uint32') && g<=intmax('uint64'))
u = 'uint64';
else
u = 'uint8';
end
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