In an assignment A(I) = B, the number of elements in B and I must be the same.

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Ahmad Sheikh
Ahmad Sheikh le 29 Oct 2015
why is this giving an error...!
A1=[2 1];
>> for i=1:2;
A(k)=[-1 1];
A(k+1)=A1+A(k);
end
  1 commentaire
Al Capwn
Al Capwn le 29 Oct 2015
Modifié(e) : Al Capwn le 29 Oct 2015
because A1+A(k) has dimensions 1x2 where as A(k+1) has dimensions 1x1.
A1+A(k)
is interpreted as
[A1(1)+A(k) A1(2)+A(k)].

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Réponses (2)

Thorsten
Thorsten le 29 Oct 2015
You cannot assign a 1x2 matrix [-1 1] to a single element A(k) of a matrix.
It is not clear to me what you want to achieve with these lines. Note that your loop uses i, but i is never used in the loop.

Eng. Fredius Magige
Eng. Fredius Magige le 29 Oct 2015
A1=[]; >> for i=1:2; i=i A1(1,1)=i.*-1 A1(1,2)=1 %k==i, you mean that A1=[A1; []] % or you mean this A1' end

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