How do I approximate the value of pi

Here is what I have so far:

function numberPI=(-1^n)*1/(2*n+1)*3^n
s=0;
n=input('enter value of n= ');
for i=1:n
    s=s+i
    numberPI
end
disp(['numberPI= ',num2str(numberPI)]);

[Dorothy Carter]

function numberPI s=0; n=input('enter value of n= '); for i=1:n s=s+i; numberPI=sqrt(12)* 1./((2*n+1).*(-3).^n; end disp(['numberPI= ',num2str(numberPI)]); Still an error.

Answer 1

[Real Name]

Are you attempting to use the Leibniz series to approximate pi? That formula you have is not correct.

[Dorothy Carter]

What is the formula then? That was what I was given Changed script: function numberPI s=0; n=input('enter value of n= '); for i=1:n s=s+i; numberPI=sqrt(12)* 1./((2*n+1).*(-3).^n; end disp(['numberPI= ',num2str(numberPI)]); Still an error.

[Real Name]

The formula is given here:

https://en.wikipedia.org/wiki/Leibniz_formula_for_%CF%80

SUM (-1)^n/(2n+1) = pi/4

So make sure to multiply the final result by 4. I'm not sure why you were given that formula. You should confirm with whomever your instructor is.