Another odd/even dilemma

I'm new to MATLAB but last year I got a lot of experience in VBA so I'm not completely untrained in code.

I have code which is running a 'for' loop controlling time values.

I have 4 sets of near exact code, but with slight edits just for classification.

Basically I'm simulating 4 cylinders and I need to display their movement, and my fourth cylinder I want to use to simulate vibration.

My query is about how I can go about saying:

"if time is odd here, position head here, else position head here"

This seems real simple but I'm having trouble because I don't have much experience with 'for' loops.

Any response would be greatly appreciated

Answer 1

[Andrei Bobrov]

t = 1:20 % "your time"
% "a" - array (vector(1x20)) of position
% "1" - position for odd time
% "2" - position for even time
a = zeros(size(t))
a(1:2:end) = 1; % odd
a(2:2:end) = 2; % even

Answer 2

[Jacque]

Thank you for your response

So how could I integrate this into my code?

I'll show you the code that I'm using and can you see if you can apply it because from reading the code you've posted I can't really see how I can get the output to effect my code:

for T4 = 0:t:Tf % Cylinder 4

V14 = V14initial + (X04*A1); V24 = V24initial + ((0.17 - X04)*A2);

% MoveDistance1 = input('Enter 1st displacement: '); % MoveDistance4 = input('Enter 2nd displacement: '); % MoveDistance4 = input('Enter 3rd displacement: ');

if mod(T4,2) Xd4 = 0.05; else Xd4 = 0.09; end

... end

This is the section of code that I'm interested in. Btw the 'mod' was merely a test and I have no clue how to use this function