for loop

if size(qq)==[1,8] 
ff=[(hh(1,1)+qq(1,2))];
ff1=[(hh(1,1)+qq(1,4))];
ff2=[(hh(1,1)+qq(1,6))];
ff3=[(hh(1,1)+qq(1,8))];
aa=kk(ff);
aa1=kk(ff1);
aa2=kk(ff2);
aa3=kk(ff3);
elseif size(qq)==[1,6] / size(qq)==[1,7]
ff=[(hh(1,1)+qq(1,2))];
ff1=[(hh(1,1)+qq(1,4))];
ff2=[(hh(1,1)+qq(1,6))];
aa=kk(ff);
aa1=kk(ff1);
aa2=kk(ff2);
elseif size(qq)==[1,4] / size(qq)==[1,5]
ff=[(hh(1,1)+qq(1,2))];
ff1=[(hh(1,1)+qq(1,4))];
aa=kk(ff);
aa1=kk(ff1);
elseif size(qq)==[1,2] / size(qq)==[1,3]
ff=[(hh(1,1)+qq(1,2))];
aa=kk(ff);
end

based on my coding, i want to calculate (aa-aa3) if the size(qq)=[1,8], (aa-aa2) if size(qq)=[1,6], (aa-aa1) of size(qq)=[1,4] and (aa only) if the size(qq)=[1,2]. Is this code correct because im not sure if it works properly.

Answer 1

[Nathan Greco]

The only thing that doesn't look right to me is where you have

elseif size(qq)==[1,#] / size(qq)==[1,#+1]

Where # is 6,4,2 Why do you have the second half there? I would get rid of that and just put

elseif size(qq)==[1,#]

And so on. Note: If you wanted to say if size(qq) is less than or equal to [1,3], you would need an | as such:

elseif size(qq)==[1,#] | size(qq)==[1,#+1]

-Nathan

[Kugen Raj]

how do I put it, if i want to calculate (aa-aa2) in the condition where size(qq)=[1,8] or size(qq)=[1,7]. i will have to put like size(qq)=[1,8] | size(qq)=[1,7] ?

[Nathan Greco]

Yes, just replace your /'s with |'s.