Why Struct contents reference from a non-struct array object occurs?

Hi, When I'm executing the code, I always face the problem 'Struct contents reference from a non-struct array object. In my program every time it is showing this error in such cases
'varnames = old.allVarNames'
Can anyone please tell me why it occurs and what should be the solution in above case?

3 commentaires

Stephen23
Stephen23 le 1 Nov 2018
Modifié(e) : Stephen23 le 1 Nov 2018
"Can anyone please tell me why it occurs and what should be the solution in above case?"
Then old is not a structure. If you expect it to be a structure, then you need to find out why it is not a structure.
You still didn’t provide enough information needed
Is old created by using load() or importdata()?

Connectez-vous pour commenter.

Réponses (3)

Set a breakfront there and then double click old in the workspace to bring it up in the variables window. Or type old on the command line. You will see its values, and that it is not a structure, but some other type of variable:
>> whos old
>> old
I always face the problem 'Struct contents reference from a non-struct array object. In my program every time it is showing this error.
Struct contents reference from a non-struct array object.
Error in updateApp (line 6)
str1 = num2str(rto1.InputPort(1).Data);
Can anyone please tell me why it occurs and what should be the solution

1 commentaire

The reason is that your rto1 variable is not a structure or static class so you can do "dot anything". Or if rto1 is a structure, then rto1.InputPort(1) is not a structure with a field called "Data".
The answer is the same as for the original poster.
Set a break point there and look in the workspace at the variable to see what it actually is. Or when stopped there, put this in the command window
>> whos rto1
>> rto1

Connectez-vous pour commenter.

Catégories

En savoir plus sur MATLAB dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by