I have
dk =
0
(49*sin(x1_k))/50 - (49*x1_k)/50
and an array X 2xn
How can I obtain the array Dk 2xn where:
Dk(1, 1)= dk calculate in the point X(1,1)
Dk(2, 1)= dk calculate in the point X(2,1)
.
.
.
thanks

1 commentaire

darova
darova le 26 Nov 2019
Looks correct for me
(49*sin(x1_k))/50 - (49*x1_k)/50 = 0

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