I am new to Matlab and using the library code for A* algorithm. I am unable to understand the array notation in it. The code snippet is as given below. I am unable to identify that which element it is access with OPEN(1,1), please help me out.

OPEN[];
OPEN(1,:)=insert_open(xNode,yNode,xNode,yNode,path_cost,goal_distance,goal_distance);
OPEN(1,1)=0;

function new_row = insert_open(xval,yval,parent_xval,parent_yval,hn,gn,fn)

new_row=[1,8];
new_row(1,1)=1;
new_row(1,2)=xval;
new_row(1,3)=yval;
new_row(1,4)=parent_xval;
new_row(1,5)=parent_yval;
new_row(1,6)=hn;
new_row(1,7)=gn;
new_row(1,8)=fn;

end

[Sachin Ganjare]

Do format the question properly, only to help yourself better.

Answer 1

[Sachin Ganjare]

insert_open function is returning a row of values.

OPEN(1,1) means 1st element of the row returned by insert_open function

Answer 2

[Walter Roberson]

OPEN(1,1) would become new_row(1,1) which is set as 1.

More generally, OPEN(1,K) would become new_row(1,K) as set in the function.

Please re-check the first line. Is it really

OPEN=[];

instead of

OPEN[];

The version without the "=" would not be valid syntax.