How can I combine values from different columns of a matrix into one single column?

Hello,
I have a matrix with three columns and many rows. The first column is the count. There are values in some sections of the second and third columns that I am not interested in. However, they do not overlap. There is no single row for which I want to extract values of both columns. I want to combine the values I am interested in in one single column, either a new column or in one of those two columns.Initially, I assigned NaN to those cells that I am not interested and then I was trying to use a loop but I am new to Matlab so it does not work. Any help will be very much appreciated. Trying to this manually in Excel takes a long time! Thanks!

 Réponse acceptée

it would be helpful to see you code so far, but i think this is what you need. A is your original matrix (nx3)
Anew=A(:,2);
index1=isnan(Anew);
Anew(index1,1)= A(index1,3)
you could do this quickly in Excel by using an "if" statement
=IF(ISNA(B1),C1,B1)

Plus de réponses (2)

Index the rows of column 3 that you want and then do a vectorized assignment. If A is your matrix and keeprows are the rows of column 3 that you want to keep,
newcol=A(:,2);
newcol(keeprows)=A(keeprows,3);

3 commentaires

Sorry. Could you help a little more? I have NaNs in sporadic sections of column 3. Those are the ones I do not want. And the ones I want have values in them and conversely those rows are assigned NaNs in column 2. Thank you.
newcol=A(:,2);
keeprows=~isnan(A(:,3));
newcol(keeprows)=A(keeprows,3);
Thank you. It did it!

Connectez-vous pour commenter.

EDIT
A=[1 4 6;2 nan 14;3 25 nan;4 78 77]
B=A
idx2=find(isnan(A(:,2)))
idx3=find(isnan(A(:,3)))
B(idx2,2)=A(idx2,3)
B(idx3,3)=A(idx3,2)

2 commentaires

But the problem is, when values in col2 and col3 are not nan, which one will you choose?
You are right although it wasn't in my case. That would be the next question. Thank you!

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by