how to choose the value?
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i have some data. see below if true
l1 = input('bus connection(choose one number from 1 to 30) = ');
bus1 = [2 3];
bus2 = [1 4 6 5];
bus3 = [1 4];
bus4 = [2 3 6 12];
bus5 = [2 7];
bus6 = [2 4 7 8 9 10 28];
bus7 = [5 6];
bus8 = [6 28];
bus9 = [6 10 11];
bus10 = [6 9 17 20 21 22];
bus11 = 9;
bus12 = [4 13 14 15 16];
bus13 = 12;
bus14 = [12 15];
bus15 = [12 14 18 23];
bus16 = [12 17];
bus17 = [16 10];
bus18 = [15 19];
bus19 = [18 20];
bus20 = [10 19];
bus21 = [10 22];
bus22 = [10 21 24];
bus23 = [15 24];
bus24 = [22 23 25];
bus25 = [24 26 27];
bus26 = 25;
bus27 = [25 28 29 30];
bus28 = [6 8 27];
bus29 = [27 30];
bus30 = [29 27];
end
when i press 1 it display bus1 matrix also when i press 2 it show bus2 matrix and bus3,bus4 etc., please anyone help me
2 commentaires
Thomas
le 14 Mai 2013
Goodwin, your code will not work as it is. I assume you want the user to input the number and then you want the corresponding bus matrix to show up..
Where do you compare what the user has entered to what you want to look up? you could do this by a number of 'if' statements (just think about it.. ) or use switch case..
win
le 14 Mai 2013
Réponse acceptée
Plus de réponses (2)
Jurgen
le 14 Mai 2013
I suggest you concatenate the numerical input l1 with the string 'bus'. Then display the content with display(). E.g.
X = ['bus' l1];
display(X)
5 commentaires
Jurgen
le 14 Mai 2013
sorry I meant you also need to use eval() since X is a string.
win
le 14 Mai 2013
Jan
le 14 Mai 2013
@godwin tgn: No, it is your turn to rewrite the code.
Do not use EVAL. It results in more troubles than it solves.
Jurgen
le 15 Mai 2013
Well it should work for this simple case?
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