How to read matrix into a variable increment?

I have a matrix A that only have data on 1st column.

How can I write this matrix as increment

t = [0:1st row data :end of row data]

help, thank you.

Answer 1

[David Sanchez]

Your question is not clear. Do you mean something like this?

A=zeros(10);
A(:,1)=rand(10,1);
B=sort(A);

Where B contains the data in A order from minimum value to maximum.

If you want to write that column in incremental form, such as

t=1:2:20
t =

       1     3     5     7     9    11    13    15    17    19

You need the first and last term and the increment between each value, supposed to be constant, otherwise you can't do as you want. You can not write in incremental notation an array like

c = [1 3 4 8 17 19 23 58]

since the increment between any two consecutive terms is different from any other

[MAIZATUL]

my data in matrix is not constant increment. so it cant be done

Answer 2

[Muruganandham Subramanian]

e.g,

>> A=[1;2;3;4;5;6];
>> t = 0 : A(1,1) : A(end,1)

Are you expecting like this??

[MAIZATUL]

i will try this, but my A is not constant increment but it is increasing

[Muruganandham Subramanian]

Is your A matrix will change randomly from time to time ?? Show ur code then?

if its having random data like below, e.g

 >> A = [ 4; 2; 7; 90; 1; 34; 6; 34; 23;];

then

 >> t = 0 : A(1,1): A(1,1) * size(A,1);

Try this

[MAIZATUL]

its ok I solved it. A = [2.345, 4.543, 5.676... end}

t = [A(1:end)] thanks!