Hello everyone,
I am trying to vectorize the creation of this symmetric matrix.
I have tried with meshgrid and ngrid, but I could not find a way to make them work with the way I use X.
Any advice?
Thank you!
X = [1:10; 2:11]';
n = length(X);
theta = .1;
Mat = zeros(n,n);
for i=1:n
for j=i+1:n
Mat(i,j)=exp(-sum(theta.*abs(X(i,:)-X(j,:)).^p));
end
end
Mat = Mat+Mat'+eye(n);

 Réponse acceptée

Marco Riani
Marco Riani le 1 Avr 2021

0 votes

% Hi, in your code p is not defined. I assume it is a scalar
% If you want to avoid the loop the answer is
% Mat=exp(-theta*(squareform(pdist(X,'minkowski',p))).^p);
% The code below checks that my implementation gives the same answer as
% your implementation
% Best
% Marco
X = [1:10; 2:11]';
p=3;
n = length(X);
theta = 0.1;
Mat = zeros(n,n);
for i=1:n
for j=i+1:n
Mat(i,j)=exp(-sum(theta.*abs(X(i,:)-X(j,:)).^p));
end
end
Mat = Mat+Mat'+eye(n);
Matchk=exp(-theta*(squareform(pdist(X,'minkowski',p))).^p);
disp(max(abs(Mat-Matchk),[],'all'))

1 commentaire

Gabriele Dessena
Gabriele Dessena le 1 Avr 2021
Modifié(e) : Gabriele Dessena le 1 Avr 2021
It works flawlessly, just a note on performance for future readers. The code is more efficient than the nested loop for n>100.
Grazie Mille Marco

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Centre d'aide et File Exchange

Produits

Version

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by