How do i reconstruct a matrix???
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George
le 21 Juin 2013
Réponse apportée : George
le 14 Oct 2013
I have a matrix 2000x3 like this:
1 1 6
1 2 8
1 3 15
....
2 1 10
2 2 20
2 3 13
....
3 1 12
3 2 18
3 3 14
...
...
and i want to reconstruct like this:
1 1 6
1 2 8
1 3 15
....
2 3 13
2 2 20
2 1 10
....
3 1 12
3 2 18
3 3 14
...
...
Please help me..
3 commentaires
Image Analyst
le 24 Juin 2013
Modifié(e) : Image Analyst
le 24 Juin 2013
The middle group has the second column flipped. But that's not enough to figure out what needs to be done in general. And what does this have to do with Image Processing, like the tag says?
Réponse acceptée
Andrei Bobrov
le 25 Juin 2013
a - your array
a1 = a;
n = unique(a(:,1));
for jj = 1:numel(n)
if rem(n(jj),2) == 0
t = a1(:,1) == n(jj);
a1(t,:) = flipud(a1(t,:));
end
end
Plus de réponses (2)
Evan
le 24 Juin 2013
M(:,:,2) = flipud(M(:,:,2))
As an example:
M = rand(3,3,3); %random example 3d matrix
M(:,:,2) = flipud(M(:,:,2));
1 commentaire
Evan
le 26 Juin 2013
In light of George's update in the below comment, this code does not do what he is asking for. http://www.mathworks.com/matlabcentral/answers/79846#comment_156778
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