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CWE Rule 570

Expression is Always False

Since R2023a

Description

Rule Description

The software contains an expression that will always evaluate to false.

Polyspace Implementation

The rule checker checks for these issues:

  • Code deactivated by constant false condition

  • Dead code

Examples

expand all

Issue

This issue occurs when a block of code is deactivated using a #if 0 directive or if(0) condition.

Risk

A #if 0 directive or if(0) condition is used to temporarily deactivate segments of code. If your production code contains these directives, it means that the deactivation has not been lifted before shipping the code.

Fix

If the segment of code is present for debugging purposes only, remove the segment from production code. If the deactivation occurred by accident, remove the #if 0 and #endif statements.

Often, a segment of code is deactivated for specific conditions, for instance, a specific operating system. Use macros with the #if directive to indicate these conditions instead of deactivating the code completely with a #if 0 directive. For instance, GCC provides macros to detect the Windows® operating system:

#ifdef _WIN32
   //Code deactivated for all operating systems
   //Other than 32-bit Windows
#endif

If you do not want to fix the issue, add comments to your result or code to avoid another review. See:

Example — Code Deactivated by Constant False Condition Error
#include<stdio.h>
int Trim_Value(int* Arr,int Size,int Cutoff) 
{
    int Count=0;

    for(int i=0;i < Size;i++){
        if(Arr[i]>Cutoff){
            Arr[i]=Cutoff;
            Count++;
        }
    }

    #if 0 //Noncompliant
    /* Defect: Code Segment Deactivated */

    if(Count==0){
        printf("Values less than cutoff.");
    }
     #endif

    return Count;
}

In the preceding code, the printf statement is placed within a #if #endif directive. The software treats the portion within the directive as code comments and not compiled.

Correction — Change #if 0 to #if 1

Unless you intended to deactivate the printf statement, one possible correction is to reactivate the block of code in the #if #endif directive. To reactivate the block, change #if 0 to #if 1.

#include<stdio.h>
int Trim_Value(int* Arr,int Size,int Cutoff) 
{
 int Count=0;

 for(int i=0;i < Size;i++)
     {
      if(Arr[i]>Cutoff)
            {
             Arr[i]=Cutoff;
             Count++;
            }
     }


 /* Fix: Replace #if 0 by #if 1 */	  
 #if 1  
      if(Count==0)
           {
            printf("Values less than cutoff.");
           }
 #endif

 return Count;
}
Issue

This issue occurs when a block of code cannot be reached because of a condition that is always true or false. This defect excludes:

Risk

Dead code wastes development time, memory and execution cycles. Developers have to maintain code that is not being executed. Instructions that are not executed still have to be stored and cached.

Dead code often represents legacy code that is no longer used. Cleaning up dead code periodically reduces future maintenance.

Fix

The fix depends on the root cause of the defect. For instance, the root cause can be an error condition that is checked twice on the same execution path, making the second check redundant and the corresponding block dead code.

Often the result details (or source code tooltips in Polyspace as You Code) show a sequence of events that led to the defect. You can implement the fix on any event in the sequence. If the result details do not show this event history, you can search for previous references of variables relevant to the defect using right-click options in the source code and find related events. See also Interpret Bug Finder Results in Polyspace Desktop User Interface or Interpret Bug Finder Results in Polyspace Access Web Interface (Polyspace Access).

See examples of fixes below.

If you see dead code from use of functions such as isinf and isnan, enable an analysis mode that takes into account non-finite values. See Consider non finite floats (-allow-non-finite-floats).

If you do not want to fix the issue, add comments to your result or code to avoid another review. See:

Example — Dead Code from if-Statement
#include <stdio.h>

int Return_From_Table(int ch){

    int table[5];

    /* Create a table */
    for(int i=0;i<=4;i++){
        table[i]=i^2+i+1;
    }

    if(table[ch]>100){ //Noncompliant
         return 0;  
    }
    return table[ch];
}

The maximum value in the array table is 4^2+4+1=21, so the test expression table[ch]>100 always evaluates to false. The return 0 in the if statement is not executed.

Correction — Remove Dead Code

One possible correction is to remove the if condition from the code.

#include <stdio.h>

int Return_From_Table(int ch){

    int table[5];

    /* Create a table */
    for(int i=0;i<=4;i++){
        table[i]=i^2+i+1;
    }

    return table[ch];
}
Example — Dead Code for if with Enumerated Type
typedef enum _suit {UNKNOWN_SUIT, SPADES, HEARTS, DIAMONDS, CLUBS} suit;
suit nextcard(void);
void do_something(suit s);

void bridge(void)
{
    suit card = nextcard();
    if ((card < SPADES) || (card > CLUBS))
        card = UNKNOWN_SUIT;

    if (card > 7) {  //Noncompliant
        do_something(card);
    }
}

The type suit is enumerated with five options. However, the conditional expression card > 7 always evaluates to false because card can be at most 5. The content in the if statement is not executed.

Correction — Change Condition

One possible correction is to change the if-condition in the code. In this correction, the 7 is changed to HEART to relate directly to the type of card.

typedef enum _suit {UNKNOWN_SUIT, SPADES, HEARTS, DIAMONDS, CLUBS} suit;
suit nextcard(void);
void do_something(suit s);

void bridge(void)
{
    suit card = nextcard();
    if ((card < SPADES) || (card > CLUBS))
        card = UNKNOWN_SUIT;

    if (card > HEARTS) {
        do_something(card);
    }
}

Check Information

Category: Expression Issues

Version History

Introduced in R2023a