Effacer les filtres
Effacer les filtres

best way to search date in vector

2 vues (au cours des 30 derniers jours)
Alina
Alina le 29 Juin 2011
hello,
i have a vector of numerical dates that repeat but not in a specific order. i need to search for all dec 1984 then do some things then search for all dec 1985 and do some things and so on until dec 2010. what is the easiest way to do it? i tried converting to string date and then concatenate but it takes too long. any suggestion on what is the best way?
many thanks, a

Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 29 Juin 2011
dev = datevec(dateinput);
dateout = sortrows(dev(dev(:,2)==12,1:3),1)

Plus de réponses (2)

Jan
Jan le 29 Juin 2011
date_numbers = [733588.513, 733688.513, 733788.513];
date_vector = datevec(date_numbers);
for year = 1984:2010
index = and(date_vector(:, 1) == i, date_vector(:, 2) == 12);
% Now "index" is the LOGICAL index, which is
% very efficient usually for selecting data.
% Perhaps "find(index)" is useful also.
end

Krishna Kumar
Krishna Kumar le 29 Juin 2011
With the description you've given, seems 'find' will do it fine- x=find(vector==1984). Seems you want to do sth like a loop- for ind=1984:2010 x=find(vector==ind); %%Your statements%% end
  1 commentaire
Alina
Alina le 29 Juin 2011
thanks but the problem is the stings is saved as a nx11 matrix (basically one cell for each character in 30-Dec-1984). if i try to concatenate this it takes too long, as n is large.

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