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I'm trying to make a Simulink model consisting of a clock (as a source) and a MATLAB function that calculates the following:
Y=exp(t) * sigma(n=1:inf)[n * exp(n*t)]
Can anybody help me write the code?
Réponses (5)
Paulo Silva
le 29 Juin 2011
MATLAB Fcn
exp(u)*sum([1:10].* exp([1:10].*u)) %not infinite sum but close enough
C.J. Harris
le 29 Juin 2011
0 votes
You won't be able to write an infinite series directly. You will either have to use an approximation, or only calculate the sum for the first 'n' elements.
Walter Roberson
le 29 Juin 2011
If and only if t is less than 0,
Y = exp(2*t)/(exp(t)-1)^2
That is, sum(n*exp(n*t), n = 1 .. infinity) is exp(t)/(exp(t)-1)^2
If t is 0 or greater, the sum is infinite, as you are adding together numbers that increase infinitely.
Hossein sadri
le 30 Juin 2011
0 votes
2 commentaires
Paulo Silva
le 30 Juin 2011
[1:10].^2
Walter Roberson
le 30 Juin 2011
n.^2 instead of n^2
But n^2*exp(u) has the same problem I described above of having an infinite value unless u is negative.
amey
le 1 Juil 2011
0 votes
n=1:1:100; y=exp(0.4)*(n.*exp(0.4*n)); tot=0; for i=1:100; tot=tot+y(i); end disp(tot);
2 commentaires
amey
le 1 Juil 2011
u = 0.4 ; % assumed
n=1:1:100; % only first 100 terms taken
Paulo Silva
le 1 Juil 2011
is there another question for us?
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