how do you write a conditional struct?

 Réponse acceptée

Walter Roberson
Walter Roberson le 18 Nov 2013
At the beginning start with
data = [];
Then, in each of the error cases, after you disp() the string, add
return
before the "end" of the "if"
if condition
disp('message')
return
end

Plus de réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 18 Nov 2013

0 votes

Maybe you are asking about if/elseif/else

4 commentaires

vishant m.
vishant m. le 18 Nov 2013
i tried using if, but it doesnt work :( can you give a simple example
Matt J
Matt J le 18 Nov 2013
Modifié(e) : Matt J le 18 Nov 2013
@vishant
Why don't you give an example of what doesn't work and describe what you want to happen instead.
vishant m.
vishant m. le 18 Nov 2013
Modifié(e) : Azzi Abdelmalek le 18 Nov 2013
function data=test3(n)
if isnumeric(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vector');
end
if isvector(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vectorl');
end
x=linspace(-5,5,1000);
y=polyval(n,x);
plot(x,y);
q=roots(n);
data=plot(q(imag(q)==0), zeros(sum(imag(q)==0)),'r+');
data= struct('x',x,'p',n,'rp',q,'rpp',q(imag(q)==0),'px',(x));
end
this is the code, you can see the struct. there are 2 if functions at the start, i need the struct to give ans[] when the condition of any of the ifs applies.
Azzi Abdelmalek
Azzi Abdelmalek le 18 Nov 2013
[i need the struct to give ans[] when the condition of any of the ifs applies.] I can't understand what you mean

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