Effacer les filtres
Effacer les filtres

For loop repetition question

1 vue (au cours des 30 derniers jours)
Todd
Todd le 29 Nov 2013
Hey guys, I'm trying to make my code below to give me N=1:10 (repeating the for loop 10 times) in addition to 1:20 and 1:50, do I need to make separate for loops for this or is there some way to get the current loop to give me this information?
clear;
x0=[42;0;95];
extinct=0;
W=zeros(1,200);
for N=[1:10]
F=2*rand(1)
for t=1:200;
W(t)=F;
A=[0 0 F; .6 0 0; 0 .75 .55];
x=(A^t)*x0;
if (sum(x)<1);
extinct=extinct+1;
break;
end
end
end
fprintf('Number of extinction events:%d\n',extinct)

Réponse acceptée

Image Analyst
Image Analyst le 29 Nov 2013
You don't need the brackets, by the way. You'd need to wrap that whole loop in another loop to handle the other top values of N:
upperN = [10,20,50]
for k = upperN
fprintf('Upper N = %d\n', k);
for n = 1 : k
fprintf(' n = %d\n', n);
end
end

Plus de réponses (1)

Roger Stafford
Roger Stafford le 29 Nov 2013
Are you certain you want matrix power in A^t rather than element-wise power as in A.^t? Either way, your coding can be made more efficient in my opinion. Also what is the point of W(t) here. It gets repeatedly erased in subsequent passes through the outer loop - that is, for each subsequent value of N the array W is overwritten, or at least partially so.

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