How can I implement a simple difference equation and plot the resulting output, all using MATLAB
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I have a simple case of all initial conditions to be zero. We can consider a general form as:
a0y(n) = b0x(n) + b1x(n-1) + b2x(n-2) + ...+ bM x(n-M)
-a1y(n-1) - a2y(n-2) - ...- aN y(n-N)
I have to plot the output y(n) with n varying from 0 to 500.
Both y(n) and x(n) are zero for n<0.
1 commentaire
Ahmed ElTahan
le 25 Mar 2016
Here is a function I have built to calculate it with added example. https://www.mathworks.com/matlabcentral/fileexchange/56142-output-estimation-difference-equation
Réponses (4)
Wayne King
le 4 Déc 2013
You have not said what x(n) is, is it a white noise input. Is it the Kronecker delta sequence.
If we don't know that x(n) is we certainly can't tell you what y(n) is.
If you know x(n), you can implement using filter
B = [b0 b1 b2 b3 .... bM];
A = [1 a1/a0 a2/a0 ... ];
x(n) = zeros(100,1);
x(1) = 1; % Kronecker delta input
y = filter(B,A,x);
Wayne King
le 5 Déc 2013
Modifié(e) : Wayne King
le 5 Déc 2013
Please look at the help for rand
x = -1+ 2*rand(100,1);
B = [b0 b1 b2 b3 .... bM];
A = [1 a1/a0 a2/a0 ... ];
y = filter(B,A,x);
sixwwwwww
le 5 Déc 2013
may be you can try something like this:
N = 500;
for n = 1:N
xValues = sum(randi(10, 1, n) .* (rand(1, n) - 1));
yValues = sum(randi(10, 1, n - 1) .* (rand(1, n - 1) - 1));
y(n) = xValues - yValues;
end
plot(1:N, y)
Mohazam Awan
le 10 Oct 2017
y1=zeros(1,length(n)); % Pre-allocating
for i=1:length(n)
if(n(i)<0)
y1(i)=0; % $ y[n]=0 for n<0
end
if (n(i)>=0)
y1(i)=y1(i-1)+x(i);
end
end
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