simple loop option to reduce code

Hi, Can anyone suggest a neat way to simply the following code.

T=0.25;
t1=-3*T/12:.001:T/12;
t2=t1(end):.001: t1(end) + T/3;
t3=t2(end):.001: t2(end) + T/3;
t4=t3(end):.001: t3(end) + T/3;
t5=t4(end):.001: t4(end) + T/3;
t6=t5(end):.001: t5(end) + T/3;
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I'm intending to use a for loop as follow but, I'm getting an error message

for r=2:6

      t(r)=t(r-1)(end):t1(end):.001: t(r-1)(end) + T/3;

end

Answer 1

[kei hin]

T=0.25;
t{1}=-3*T/12:.001:T/12;
for r=2:6
      t{r} = t{r-1}(end):.001: t{r-1}(end) + T/3;
end

[Rashmil Dahanayake]

Thanks. ^Cell array option is more concise

Answer 2

[Rashmil Dahanayake]

figured it out

T=0.25;
t1=-3*T/12:.001:T/12;
Time(1,:)=t1;
for r=2:6
    Time(r,:)=Time((r-1),end):.001: Time((r-1),end) + T/3;  
end

Answer 3

[Andrei Bobrov]

T = .25;
n = 6;
tt = -3*T/12:.001:T/12;

Time1 = bsxfun(@plus,tt,diff(tt([1,end]))*(0:n-1)');