HELP WITH ESTRACT SUBSTRING OF STRING
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
good, I wish to raise my problem, because I know how to do. I, for example have a long string as follows:
[3 -1 -1 -1 -1 -1 1 -1 -1 -1 0 -1 -1 -1 -1 4 -1 0 -1 -1 -1 0 -1 -1 3 -1 -1 -1 -1 -1 -1 4 -1 -1 0
-1 1 -1 -1 -1 0 -1 1 -1 -1 -1 -1 -1 -1 1 -1 0 -1 -1 4……..
What I want to do is the following:
1) extracting substrings so that starts for next 3/4 and ends 3/4 including the upcoming latter. For example:
[-1 -1 -1 -1 -1 1 -1 -1 -1 0 -1 -1 -1 -1 4]
Next substring;
[-1 0 -1 -1 -1 0 -1 -1 3]
Next substring;
[-1 -1 -1 -1 -1 -1 4]
And so on
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Réponses (3)
Walter Roberson
le 11 Déc 2013
regexp(String, '(?<=[34]).*?[34]', 'match')
Or so I figure as I drift off to sleep.
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Andrei Bobrov
le 11 Déc 2013
a = [3 -1 -1 -1 -1 -1 1 -1 -1 -1 0 -1 -1 -1 -1 4 -1 0 -1 -1 -1 0 -1 -1 3 -1 -1 -1 -1 -1 -1 4 -1 -1 0 -1 1 -1 -1 -1 0 -1 1 -1 -1 -1 -1 -1 -1 1 -1 0 -1 -1 4];
l = a == 3 | a== 4;
l(2:end-1) = circshift(l(2:end-1),[0 1]);
l(end) = 0;
out = accumarray(cumsum(l(:)),a(:),[],@(x){x});
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Jos (10584)
le 11 Déc 2013
If you have version 2013b, there is a function called strsplit , that might work on numerical arrays (like strfind used to do). I cannot test this, though.
C = strsplit(str,[3 4])
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