How to work on fprintf in fopen?
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Hi team,
I am using following code
[ftxt,msg] = fopen([textpath keyword '_summary.txt' ],'w');
fprintf(ftxt, 'Summary sheet of %12s\n\n', TR);
and i am getting error as
Error using fprintf
Invalid file identifier. Use fopen to generate a valid file identifier.
Please help me solving this problem.
Réponses (1)
Wayne King
le 23 Déc 2013
0 votes
What is msg? That is the system-dependent error message returned by fopen. I'm assuming the value of txt is -1 meaning the fopen() operation did not work.
2 commentaires
Radhika
le 23 Déc 2013
Wayne King
le 23 Déc 2013
I'm afraid you need to provide us with more information than you have given. Are we supposed to know what textpath is or keyword?
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