its not taking the values of y when y value is ranging from 0.25 to 0.45 with an interval of 0.05,but it is able to take the value when y value is constant. and its coming in some matrix but with constant values.
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Y1 = 7.7054
Y2 = 9.6584
I(3)= -0.0043
I(4)=0.4141
n=4 ;
m=2;
y=0.25:0.05:0.45;
for j=1:m
for i=1:n
if (j==1)
ud(i+1,1)=y;
taub(i+1,1)=y;
ud(i+1,2)=(I(3)*exp(Y2*y)+I(4)*exp(-Y2*y)+k2)^0.5;
taub(i+1,2)=(f*ro*ud(i+1,2)^2)/8;
end
end
end
ud
taub
plot(ud(i,1),ud(i,2))
sir here y will be my first column and ud will be my second column,bt ud is dependent on y,y is varying from 0.25 to 0.45 by having an interval of 0.05. here i just want to change the value of y in each iteration.
7 commentaires
ES
le 23 Jan 2014
Shouldn't you be using y(i) instead of y alone in the lines
ud(i+1,1)=y;
taub(i+1,1)=y;
ud(i+1,2)=(I(3)*exp(Y2*y)+I(4)*exp(-Y2*y)+k2)^0.5;
Also what is k2?
ellora
le 24 Jan 2014
Image Analyst
le 24 Jan 2014
But we don't know if y should really be y(j) or y(i). y has 5 elements, not 2 or 4 like m and n.
ellora
le 24 Jan 2014
Image Analyst
le 24 Jan 2014
Is "the table" what you call "taub"? And by "find" you really mean "assign"? Or do you really mean "find" as in search for, or identify the location of?
ellora
le 25 Jan 2014
ellora
le 26 Jan 2014
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