Fit a circle to 3d dots

4 vues (au cours des 30 derniers jours)
ELI
ELI le 31 Jan 2014
Hi, I have dots spread like a tube in a 3d space. I want to fit a circle to this data (the data is attached). The plane that the circle should be in is:
S1=[-15.8,8.6,1.3];
S2=[-10.5,10.3,-3.3];
S3=[-15.2,8.9,1.6];
normal = cross(S1-S2, S1-S3);
A = normal(1); B = normal(2); C = normal(3);
D = dot(normal,S1);
This is what I was trying to do:
plot3(n1,n2,n3,'*') %The dots
hold on
a2=[mean(n1),mean(n2),mean(n3)]; %Center of the dots
plot3(a2(1),a2(2),a2(3),'*','color','g')
a3=dist(a2,[n1;n2;n3]); %calculate the radius
t = linspace(0,2*pi,40);
x=(mean(a3).*sin(t)+mean(n1));
y=(mean(a3).*cos(t)+mean(n2));
z = (A * x + B * y - D)/(-C);
plot3(x,y,z,'*','color','r')
But I can't set the circle right in place (it is grater than what it should be). could you help?
  1 commentaire
ELI
ELI le 31 Jan 2014
The dots data are attached.

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Réponse acceptée

Mischa Kim
Mischa Kim le 31 Jan 2014
There is probably something not working with the way you rotate the circle back into the plane. This works:
S1=[-15.8,8.6,1.3];
S2=[-10.5,10.3,-3.3];
S3=[-15.2,8.9,1.6];
normal = cross(S1-S2, S1-S3); % compute reference frame axes
nz = normal'/norm(normal);
normal2 = cross(nz, [0; 1; 0]);
nx = normal2/norm(normal2);
ny = cross(nz, nx)/norm(cross(nz, nx)); % end compute reference frame axes
R = [nx ny nz]; % compute rotation matrix
plot3(n1,n2,n3,'*') %The dots
hold on; grid; box;
a2=[mean(n1),mean(n2),mean(n3)]; %Center of the dots
plot3(a2(1),a2(2),a2(3),'*','color','g')
a3=dist(a2,[n1;n2;n3]); %calculate the radius
t = linspace(0,2*pi,40);
x0=(mean(a3).*sin(t)); % get circle coordinates in x-y plane...
y0=(mean(a3).*cos(t));
z0 = zeros(1,length(x0));
xyz = bsxfun(@plus, R*[x0; y0; z0], a2'); % rotate circle plane and adjust center
plot3(xyz(1,:),xyz(2,:),xyz(3,:),'-','color','r')

Plus de réponses (1)

Iain
Iain le 31 Jan 2014
Without looking at the data, it looks like the size of your circle would be larger than it should be because of the spots being off the plane where your circle exists.
Either you should reform your formula to fit the best circle in 3D space (that should be a page or two of working out the formulae), or, you should calculate the closest point on your plane to each point, and then use those points to fit your circle.
  1 commentaire
ELI
ELI le 31 Jan 2014
The circle should be in the edge of the tube like dots.

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