reshape a matrix with a divisible of 10....

i wanted to reshape my a matrix of size 1*N into 10 rows N/10 columns... but when N is not divisible by 10 i get error... how can i rectify the error?? either pad it with zeros to get a number divisible by 10 or get the previous number divisible by 10....

that is if my matrix

 A = 1 * 100
 i need output B to be 10*10 output

 but if A = 1*111.... 
 i get error, so i want to convert 
 A to 1 * 120 and get B = 10*12 or

 change A to 1*110 and get B = 10*11 new output....

please do reply me....

Answer 1

[Andrei Bobrov]

r = 10;

out = reshape([A(:);nan(mod(-numel(A),r),1)],r,[])

ADD

out = reshape(A(1:fix(numel(A)/r)*r),r,[])

[Elysi Cochin]

sir which one should i do... isnt both the out variable is same??? what is the difference??

[Andrei Bobrov]

This is a different solutions, for example:

A =randi(25,1,27)
r = 10;
out1 = reshape([A(:);nan(mod(-numel(A),r),1)],r,[]) % first variant
out2 = reshape(A(1:fix(numel(A)/r)*r),r,[])         % second variant

Answer 2

[Azzi Abdelmalek]

A=rand(87,1);
n=(10-mod(numel(A),10));
n=n*sign(n);
A(end+1:end+n)=0;
out=reshape(A,10,[])

%or

r=10
m=numel(A);
out=reshape([A;zeros(ceil(m/r)*r-m,1)],r,[])

Answer 3

[Iain]

To pad it with 0's:

 if mod(numel(A),10)
  A(ceil(numel(A)/10)*10) = 0;
 end
 B = reshape(A,10,[]);

To pad with NaNs...

 if mod(numel(A),10)
  A(end+1:ceil(numel(A)/10)*10) = NaN;
 end
 B = reshape(A,10,[]);

To use the previous divisible:

 A((floor(numel(A)/10)*10+1):end) = [];
 B = reshape(A,10,[]);

Answer 4

[Anuj]

Try this, its very simple-

n=10-mod(numel(A),10);
if n==10;
reshape(A,10,numel(A)/10)
else
A=padarray(A,[0,n],'post');
reshape(A,10,numel(A)/10)
end

[Elysi Cochin]

thank u all....