Effacer les filtres
Effacer les filtres

Finding structure array entries with certain values

304 vues (au cours des 30 derniers jours)
Tom
Tom le 7 Mar 2014
Modifié(e) : Thomas le 7 Mar 2014
Hello,
What is the way to find all structure array entries with specific values?
E.g. I tried:
find(cell_data.CN == 4)
But that returns:
Error using ==
Too many input arguments.
Kind regards,
Tom

Réponse acceptée

Jos (10584)
Jos (10584) le 7 Mar 2014
I assume that celldata is a structure array
% create some example data
for k=1:10, celldata(k).CN = ceil(4*rand) ; end
% method 1: easy
allCN = [celldata.CN] % comma separated list expansion
tf1 = allCN == 4
index1 = find(tf1)
% method 2: very flexible
fun = @(x) celldata(x).CN == 4 % useful for complicated fields
tf2 = arrayfun(fun, 1:numel(celldata))
index2 = find(tf2)
Both methods can be written as one-liners.

Plus de réponses (1)

Thomas
Thomas le 7 Mar 2014
You could use something like this
strs={'1' '2' '3' '4'}
ind=find(ismember(strs,'4'))
>> ind =
4
  2 commentaires
Tom
Tom le 7 Mar 2014
What is strs? I tried replacing strs with cell_data.CN there and got
Error using ismember (line 68) Too many input arguments.
So I don't think I understand properly your suggestion...
Thomas
Thomas le 7 Mar 2014
Modifié(e) : Thomas le 7 Mar 2014
strs in the array of cells.. that I am defining above the find command to give the example..
try
strs ={cel_data.CN};
ind=find(ismember(strs,'4'))

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