Effacer les filtres
Effacer les filtres

Date conversion in a number format

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Md
Md le 27 Mar 2014
Commenté : Walter Roberson le 27 Mar 2014
Hey guys
I have an excel file with the date format like this: '03/06/2014 11:39:04.324 PM' I want to convert this date format into (yyyymmddhhmmssSSS)20140306233904324. If the time is PM, then the hour should be in the format of 24 hours. Thanks in advance.

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Chandrasekhar
Chandrasekhar le 27 Mar 2014
clc
str = '03/06/2014 11:39:04.324 PM';
[date,rem] = strtok(str,'/');
[month,rem]= strtok(rem,'/');
[year,rem]=strtok(rem,' ');
year = regexprep(year,'/','');
[hours,rem]=strtok(rem,':');
hours = regexprep(hours,' ','');
[mins,rem] = strtok(rem,':');
[sec,rem]=strtok(rem,'.');
sec = regexprep(sec,':','');
[msec,rem]= strtok(rem,' ');
[msec,y] = strtok(msec,'.');
if(strcmp(rem,' PM'))
hours = str2num(hours);
hours = hours+12;
hours = num2str(hours);
end
totaltime = [year date month hours mins sec msec]

Plus de réponses (1)

Walter Roberson
Walter Roberson le 27 Mar 2014
datestr(datevec('03/06/2014 11:39:04.324 PM', 'MM/DD/YYYY hh:mm:ss.fff PM'), 'YYYYMMDDhhmmssfff')
  2 commentaires
Chandrasekhar
Chandrasekhar le 27 Mar 2014
so simple..
Walter Roberson
Walter Roberson le 27 Mar 2014
You could also use datenum instead of datevec but I think datevec should be more resistant to round-off.

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