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What determines the shape of a logically indexed array?

4 vues (au cours des 30 derniers jours)
Ondrej Budac
Ondrej Budac le 3 Avr 2014
Matlab help explains: " Logical Indexing : ... The output is always in the form of a column vector."
In practice, typing
a = ones(3,3);
b = a([true, true]);
gives a row vector b. Can someone tell me why does it behave this way? And is there any other instance (apart from indexing by one row logical vector) that gives a non-column result? Thanks, O.

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Ondrej Budac
Ondrej Budac le 7 Avr 2014
Just to complete the story, the answer seems to be:
If B is a logical array and A is any array, then A(B) is equivalent (but faster) way to produce the same result as A(find(B)), including the shape of the output.

Plus de réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 3 Avr 2014
Maybe you need
a = ones(3,3);
b = a([true, true],:)
  7 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 3 Avr 2014
Just one question, what are you expecting with a(logical([1 0;1 1])) ? The result contains 3 elements
Ondrej Budac
Ondrej Budac le 3 Avr 2014
If I now understand logical indexing correctly, I expect a(logical([1 0;1 1])) to give a column vector with values 1, 4, 2, assuming your definition of a.

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