Effacer les filtres
Effacer les filtres

Creating Matrix using nested for loop?

1 vue (au cours des 30 derniers jours)
Sima
Sima le 6 Avr 2014
how would i create the following matrix using a nested for loop?
[3 6 9 12 15;
4 8 12 16 20;
7 14 21 28 35]
so far i have: m=3;
n=5;
C=zeros(m,n);
for j=1:n
for i=1:m
C(i,j) =
end
end
  2 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 6 Avr 2014
For the first column, why 3, 4 then 7 ?
Sima
Sima le 6 Avr 2014
its a question that practices making certain matrices using a nested for loop and the answer has to contain a nested for loop

Connectez-vous pour commenter.

Réponses (3)

Azzi Abdelmalek
Azzi Abdelmalek le 6 Avr 2014
Maybe you want this
n=5;
m=6;
out=cell2mat(arrayfun(@(x) x:x:n*x,(1:m)','un',0))

Roger Stafford
Roger Stafford le 7 Avr 2014
How about
C = [3;4;7]*(1:5);
or
C = zeros(3,5);
for r = [3,4,7]
for c = 1:5
C(r,c) = r*c;
end
end
  1 commentaire
Alberto
Alberto le 7 Avr 2014
m=3; n=5; C=zeros(m,n); A=[3 4 7]; for k=1:length(A) for j=1:5 C(k,j)= A(k)*j end end

Connectez-vous pour commenter.


Lam Nguyen Van
Lam Nguyen Van le 10 Mar 2020
Hi,
I want to creat matrices automatically with for loop in Matlab?
phi1=30; phi2=45; phi3=90;
After running the code I want to have a matric A with the following elements:
A=[sin(phi1) cos(phi1) sin(phi1)*cos(phi1);
sin(phi2) cos(phi2) sin(phi2)*cos(phi2);
sin(phi3) cos(phi3) sin(phi3)*cos(phi3);]
Thanks.

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by