How to retain only the rows of a matrix based on the unique numbers in the first column of the matrix?

5 vues (au cours des 30 derniers jours)
Hello guys Say that a=[1 3 3; 1 4 3; 2 4 3; 2 5 2; 2 4 2; 3 2 1; 4 3 4; 4 3 2] I need to keep the rows where I have only unique numbers in the first column of the matrix. That means I want to have this matrix a= [1 3 3; 2 4 3; 3 2 1; 4 3 4]. Or I also need to get [1 4 3; 2 4 2; 3 2 1; 4 3 2]. That means retaining the last unique row (based on only the first column) instead of the first. Are they possible? please help.
Kind regards
Sayeed

Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 22 Avr 2014
Modifié(e) : Azzi Abdelmalek le 22 Avr 2014
[ii,jj,kk]=unique(a(:,1),'stable');
out1=a(jj,:)
out2=cell2mat(accumarray(kk,1:numel(kk),[],@(x) {a(max(x),:)}));
  1 commentaire
Mohammad Sayeed
Mohammad Sayeed le 22 Avr 2014
Dear Brother It was just perfect! Thank you very much for your kind solution. By applying your codes, I have got both the matrix that I was looking for. Thanks again.
Sayeed

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Plus de réponses (1)

Andrei Bobrov
Andrei Bobrov le 22 Avr 2014
Modifié(e) : Andrei Bobrov le 22 Avr 2014
[~,b] = unique(a(:,1),'first');
out1 = a(b,:);
out2 = a([b(2:end)-1;size(a,1)],:);
or
[~,b1] = unique(a(:,1),'first');
[~,b2] = unique(a(:,1),'last');
out1 = a(b1,:);
out2 = a(b2,:);

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