Generate automatically vectors of precise length and given values

Hello
I want to automatically construct a vector of user defined size using a set of elements defined within a second vector by filling the 1st vector linearly.
As a small example
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
vector_2 = [1,100,2,100,3,100,4]
length_vector_1 = 12
% vector to be automatically generated
vector_1 = [1,100,2,100,3,100,4,100,1,100,2,100]
length_vector_1 = 3
% vector to be automatically generated
vector_1 = [1,100,2]
Is there a way to generate such vectors ?
Thanks in advance

 Réponse acceptée

José-Luis
José-Luis le 23 Mai 2014
Modifié(e) : José-Luis le 23 Mai 2014
vector_2 = [1,100,2,100,3,100,4];
numVal = 19;
your_vec = repmat(vector_2,1,ceil(numVal/numel(vector_2)));
your_vec = your_vec(1:numVal);
Please accept an answer if it helped you.

Plus de réponses (1)

No need to create an intermediate vector with repmat that could be much longer than the final one. Just use simple indexing into the original vector:
vector_2 = [1,100,2,100,3,100,4];
length_vector_1 = 19;
vector_1 = vector_2(rem(0:length_vector_1 - 1, numel(vector_2))+1)

2 commentaires

Here's the trade-off:
vector_2 = rand(1,777777);
numVal = 100000000;
tic
your_vec = repmat(vector_2,1,ceil(numVal/numel(vector_2)));
your_vec = your_vec(1:numVal);
toc
vector_1 = vector_2(rem(0:numVal - 1, numel(vector_2))+1);
toc
Elapsed time is 3.062471 seconds.
Elapsed time is 5.132982 seconds.
Indeed, my code is faster!
(You forgot to put a tic …)

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by