Effacer les filtres
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about logical operator in if!

1 vue (au cours des 30 derniers jours)
chan
chan le 25 Mai 2014
Clôturé : MATLAB Answer Bot le 20 Août 2021
This is my code
y = input('choose','s');
if y == 'a1' | y == '1a'
disp('win')
else
disp('lost')
end
I would like to ask that when I use this, while I am run this program, I type only a or only 1 it also display win, like i type 1a or a1 . explain to me, or me have other ways to write the code, I do not need to add elseif more.
Thanks!

Réponses (1)

Matt J
Matt J le 25 Mai 2014
Modifié(e) : Matt J le 25 Mai 2014
Use strcmp()
if strcmp(y,'a1') || strcmp(y,'1a')
disp('win')
else
disp('lost')
end
As for understanding what's happening currently, observe the result of each of your sub-expressions, and the vectors of logical data they produce, when y='1',
>> y='1';
>> y == 'a1'
ans =
0 1
>> y == '1a'
ans =
1 0
>> y == 'a1' | y == '1a'
ans =
1 1
Since (y == 'a1' | y == '1a') produces a vector of trues, the whole if statement evaluates to true. As mentioned in "doc if",
" An evaluated expression is true when the result is nonemptyand contains all nonzero elements (logical or real numeric). Otherwise,the expression is false. "
  5 commentaires
Matt J
Matt J le 26 Mai 2014
Modifié(e) : Matt J le 26 Mai 2014
to see if two things are equal use isequal, ... isequal(y,'a1')
Be careful when using isequal to compare strings. It doesn't check that both arguments are class char, e.g.,
>> isequal(':',58)
ans =
1
whereas,
>> strcmp(':',58)
ans =
0
Matt J
Matt J le 26 Mai 2014
so mean we cannot use the simple condition, right? y == 'a1' | y == 'a1'
You can use these kinds of comparisons when they are appropriate to what you are doing. For example, suppose I want to remove all the spaces in a string,
>> y='This is a short string'; y(y==' ')=''
y =
Thisisashortstring

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