Sum of the elements of rows of matrix

21 vues (au cours des 30 derniers jours)
Akmyrat
Akmyrat le 28 Mai 2014
Commenté : Jos (10584) le 29 Mai 2014
lets say i have A=[1 2 1;3 2 1;3 5 4] and i want to sum up row elements separately and show me results as "Ri=..." here "i" is number of row. in this case R1=7, R2=9. R3=6.
  1 commentaire
Matt J
Matt J le 28 Mai 2014
It sounds like you really mean "sum up column elements". The elements you are summing all belong to a common column, not a common row.

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Réponse acceptée

Matt J
Matt J le 28 Mai 2014
Modifié(e) : Matt J le 28 Mai 2014
Asum=sum(A,1);
for i=1:length(Asum)
disp(['R' num2str(i) '=' num2str(Asum(i))]);
end
  4 commentaires
Matt J
Matt J le 28 Mai 2014
Hurts in what way? As you recommended, I do not autogenerate separate variables R1, R2, R3,...
Jos (10584)
Jos (10584) le 29 Mai 2014
:-) Indeed, you exactly did what Akmyrat asked for ...

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Plus de réponses (2)

Chandrasekhar
Chandrasekhar le 28 Mai 2014
sum(A')
  2 commentaires
Matt J
Matt J le 28 Mai 2014
Modifié(e) : Matt J le 28 Mai 2014
This won't work if A is a row vector. Transposing is also expensive in computation time and memory if A is large.
Chandrasekhar
Chandrasekhar le 28 Mai 2014
Please let us know what is best way to do this?

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Jos (10584)
Jos (10584) le 28 Mai 2014
You do not want to store the results in separate variables R1, R2, etc., but rather as elements of a single variable R, with R(1), R(2), etc.
A = magic(3)
RowSum = sum(R,2)
help sum
  2 commentaires
Akmyrat
Akmyrat le 28 Mai 2014
Hi jos, thanks. but sorry your code also not working.
Jos (10584)
Jos (10584) le 28 Mai 2014
What do you mean, "not working"? Did you read the help of sum?
May be you want to sum along rows rows, i.e., sum the elements in each column?
ColumnSum = sum(R,1)
Next time, be a little bit more specific ...

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