Split along word into parts with different lengths

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Brasco , D.
Brasco , D. on 6 Jun 2014
Edited: Brasco , D. on 1 Sep 2016
problem solved
  3 Comments
dpb
dpb on 6 Jun 2014
Specifically, what's the rule for breaking down the first set of six letters into the two groups of three if that isn't a consistent string. If it is, then just substring referencing of 1:3 and 4:6 takes care of it.
The rest looks like looking for capitals after a lowercase letter.

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Accepted Answer

Cedric Wannaz
Cedric Wannaz on 6 Jun 2014
Edited: Cedric Wannaz on 6 Jun 2014
Here is a solution based on comments above. Yet, we will need you to answer these comments so we can refine the approach. Assuming
data = {'NCCINS.AttitudePositionINS1.Pitch', 'NCCINS.AttitudePositionINS1.Roll'} ;
we perform a single call to REGEXP on a comma-separated merger of the original strings, as follows:
pattern = '(\w{3})(\w{3}).(.[^A-Z]+)(.[^A-Z]+)([^\.]+).([^,]+)' ;
tokens = regexp( sprintf('%s,', data{:}), pattern, 'tokens' ) ;
with that, we get
>> tokens{1}
ans =
'NCC' 'INS' 'Attitude' 'Position' 'INS1' 'Pitch'
>> tokens{2}
ans =
'NCC' 'INS' 'Attitude' 'Position' 'INS1' 'Roll'
  1 Comment
Cedric Wannaz
Cedric Wannaz on 6 Jun 2014
Can you attach a few example, or one package, or even the 70. The more I have, the more I can refine the approach. The approach above is based on regular expressions and pattern matching. I cannot explain it generally because there would be way too much to develop. Yet, once we have a pattern which suites your case specifically, I can explain it to you.

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