# How to colour a 3D image with a continuous spectrum of colours

3 vues (au cours des 30 derniers jours)
Matlab2010 le 17 Juin 2014
Modifié(e) : Cedric le 18 Juin 2014
I have a 3D image. I would like to shade it in a continuous colour. I.e. where the colour of the image is conditional on its location in 3D space. How can I do this for for my image? For example:
My code to generate the image is below.
thanks
%www.mathworks.co.uk/matlabcentral/fileexchange/30923-fast-stl-import-function
%www.cs.technion.ac.il/~gershon/EscherForReal/PenroseTriangleStl1.zip
myStr = 'D:\PenroseTriangle.stl';
[vertices, norms] = import_stl_fast(myStr,2);
n = length(vertices)/3;
X = reshape(vertices(:,1),3,n);
Y = reshape(vertices(:,2),3,n);
Z = reshape(vertices(:,3),3,n);
C = zeros(3,n);
%%Render
figure;
set(gcf, 'Color', 'white');
as = 0.95;
strt=1;
stop=6000;
patch(X(:,strt:stop),Y(:,strt:stop),Z(:,strt:stop),C(:,strt:stop),...
'FaceColor', [0 0 1], ...
'EdgeColor', 'none', ...
'FaceLighting', 'phong', ...
'AmbientStrength', as);
strt=6001;
stop=6299;
patch(X(:,strt:stop),Y(:,strt:stop),Z(:,strt:stop),C(:,strt:stop),...
'FaceColor', [0 1 0], ...
'EdgeColor', 'none', ...
'FaceLighting', 'phong', ...
'AmbientStrength', as);
strt=6300;
stop=6719;
patch(X(:,strt:stop),Y(:,strt:stop),Z(:,strt:stop),C(:,strt:stop),...
'FaceColor', [1 0 0], ...
'EdgeColor', 'none', ...
'FaceLighting', 'phong', ...
'AmbientStrength', as);
view([-135 35]);
axis('image');
axis('off');
% colormap('hsv');
material('shiny');
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### Réponse acceptée

Jason Nicholson le 17 Juin 2014
Modifié(e) : Jason Nicholson le 17 Juin 2014
The patch command's fourth argument, C, is the color of the that patch. Your C matrix is C=0. That is the problem. Instead use a function that defines the color matrix C. Matlab will scale C matrix to the default color values.
Try this:
% Euclidean distance in 3d
C = sqrt(X.^2 + Y.^2 + Z.^2);
Here is what it does to your code:
%www.mathworks.co.uk/matlabcentral/fileexchange/30923-fast-stl-import-function
%www.cs.technion.ac.il/~gershon/EscherForReal/PenroseTriangleStl1.zip
myStr = 'PenroseTriangle.stl';
[vertices, norms] = import_stl_fast(myStr,2);
n = length(vertices)/3;
X = reshape(vertices(:,1),3,n);
Y = reshape(vertices(:,2),3,n);
Z = reshape(vertices(:,3),3,n);
C = sqrt(X.^2 + Y.^2 + Z.^2);
%%Render
figure;
set(gcf, 'Color', 'white');
as = 0.95;
strt=1;
stop=6000;
patch(X(:,strt:stop),Y(:,strt:stop),Z(:,strt:stop),C(:,strt:stop),...
'FaceColor', 'interp', ...
'EdgeColor', 'none', ...
'FaceLighting', 'phong', ...
'AmbientStrength', as);
strt=6001;
stop=6299;
patch(X(:,strt:stop),Y(:,strt:stop),Z(:,strt:stop),C(:,strt:stop),...
'FaceColor', 'interp', ...
'EdgeColor', 'none', ...
'FaceLighting', 'phong', ...
'AmbientStrength', as);
strt=6300;
stop=6719;
patch(X(:,strt:stop),Y(:,strt:stop),Z(:,strt:stop),C(:,strt:stop),...
'FaceColor', 'interp', ...
'EdgeColor', 'none', ...
'FaceLighting', 'phong', ...
'AmbientStrength', as);
view([-135 35]);
axis('image');
axis('off');
colormap('hsv');
material('shiny');
##### 6 commentairesAfficher 4 commentaires plus anciensMasquer 4 commentaires plus anciens
Image Analyst le 18 Juin 2014
OK - that sounds about right/typical (for everyone except Greg of course!) And too bad Walter (our most prolific contributor to date) seems to have fallen off the planet. Wonder what happened to him. One time before he left for about 3 months before coming back so maybe he'll return some day.
Cedric le 18 Juin 2014
Modifié(e) : Cedric le 18 Juin 2014
Yes I was wondering as well. Hopefully he is just on a sunny island and was wise enough not to take his keyboard! Speaking of ratio, I built the code attached lately, just for fun (well, I was waiting at a bus stop, so .. "for more fun than just waiting").

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