Error unexpected matlab operator

Hi, every body
i try to execute the code given in the help of matlab, but there is something wrong, this is the code:
if true %code f:=plot::Function2d(sin(x),x=0..2*PI)
f:=plot::Function2d(sin(x),x=0..2*PI) | Error: The expression to the left of the equals sign is not a valid target for an assignment. end
so i clik on the space bar after "f" the code will be like this:
if true %code f :=plot::Function2d(sin(x),x=0..2*PI)
Undefined function 'f' for input arguments of type 'char'. end
i delete "f", the code will be like:
if true %code plot::Function2d(sin(x),x=0..2*PI)
plot::Function2d(sin(x),x=0..2*PI) | Error: Unexpected MATLAB operator.
end
same result for the belowing codes
if true %code plot(plot::Function2d(sin(x),x=0..2*PI)) end
and
if true %cdoe plot(plot::Function2d(sin(x),x=0..2*PI)): end
and if true %code plot(plot::Function2d(sin(x),x=0..2*PI)); end
so if the codes in the help deosn't work, how can i learn matlab?
my matlab version is complete, 64 bits, 2013b on windows 7.

2 commentaires

Matt J
Matt J le 18 Juin 2014
If you font your code using this button,
I will up-vote your question.
Aws
Aws le 18 Juin 2014
i think it deosn't work exactly the "code"

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Réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 18 Juin 2014

0 votes

This looks like Mupad code, You have to look at Mupad help
doc mupad
If you are new with matlab, then begin with Matlab getting started

1 commentaire

Aws
Aws le 18 Juin 2014
Modifié(e) : Aws le 18 Juin 2014
thank you Abdelmalek, that's true it's a mupad code. Salem alaykom. Have a nice day.

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Question posée :

Aws
le 18 Juin 2014

Modifié(e) :

Aws
le 18 Juin 2014

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