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Easy Question, update scatter point in loop

15 vues (au cours des 30 derniers jours)
Yuang
Yuang le 24 Juin 2014
Commenté : Ben11 le 24 Juin 2014
Hi:
I just want to get the 4 vectors scatter update every time in my loop. Delete the last time points then plot then hold on to new loop.
How to do that??
Thank you.
x1{1} = [.2; .3]; x2{1} = [.3; .4]; x3{1} = [.5; .6]; x4{1} = [.6; .7]; k = 1;
for k = 1:1:50
scatter(x1{k}(1,1), x1{k}(2,1));
hold on
scatter(x2{k}(1,1), x2{k}(2,1));
hold on
scatter(x3{k}(1,1), x3{k}(2,1));
hold on
scatter(x4{k}(1,1), x4{k}(2,1));
x1{k+1} = (x1{k} + x2{k} + x4{k})/3;
x2{k+1} = (x1{k} + x2{k} + x3{k})/3;
x3{k+1} = (x2{k} + x3{k} + x4{k})/3;
x4{k+1} = (x1{k} + x3{k} + x4{k})/3;
end

Réponse acceptée

Ben11
Ben11 le 24 Juin 2014
What if you try this:
x1{1} = [.2; .3]; x2{1} = [.3; .4]; x3{1} = [.5; .6]; x4{1} = [.6; .7]; k = 1;
figure
for k = 1:1:50
hold all
scatter(x1{k}(1,1), x1{k}(2,1))
scatter(x2{k}(1,1), x2{k}(2,1));
scatter(x3{k}(1,1), x3{k}(2,1));
scatter(x4{k}(1,1), x4{k}(2,1));
x1{k+1} = (x1{k} + x2{k} + x4{k})/3;
x2{k+1} = (x1{k} + x2{k} + x3{k})/3;
x3{k+1} = (x2{k} + x3{k} + x4{k})/3;
x4{k+1} = (x1{k} + x3{k} + x4{k})/3;
hold off
drawnow
end
First you create a figure, then you force the plot to update with drawnow. You can keep the original "hold on" calls and see what it does as well.
  12 commentaires
Yuang
Yuang le 24 Juin 2014
Sorry. I mean I want the figure shows the path x1,x2,x3 and x4 go.
Ben11
Ben11 le 24 Juin 2014
ok. Do you mean something like this:
for k = 1:50
scatter(x1{k}(1,1), x1{k}(2,1))
if k > 1
line([x1{k-1}(1,1) x1{k}(1,1)],[x1{k-1}(2,1) x1{k}(2,1)],'Color','r');
end
drawnow
hold on
scatter(x2{k}(1,1), x2{k}(2,1));
if k > 1
line([x2{k-1}(1,1) x2{k}(1,1)],[x2{k-1}(2,1) x2{k}(2,1)],'Color','g');
end
drawnow
hold on
scatter(x3{k}(1,1), x3{k}(2,1));
if k > 1
line([x3{k-1}(1,1) x3{k}(1,1)],[x3{k-1}(2,1) x3{k}(2,1)],'Color','b');
end
drawnow
hold on
scatter(x4{k}(1,1), x4{k}(2,1));
if k > 1
line([x4{k-1}(1,1) x4{k}(1,1)],[x4{k-1}(2,1) x4{k}(2,1)],'Color','k');
end
drawnow
hold on
x1{k+1} = (x1{k} + x2{k} + x4{k})/3;
x2{k+1} = (x1{k} + x2{k} + x3{k})/3;
x3{k+1} = (x2{k} + x3{k} + x4{k})/3;
x4{k+1} = (x1{k} + x3{k} + x4{k})/3;
hold off
pause(.1)
end
I seems odd is it what you would expect?

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Plus de réponses (1)

Geoff Hayes
Geoff Hayes le 24 Juin 2014
Try grabbing the handle returned from each scatter call and then deleting that on subsequent iterations. Outside the for loop declare an array to manage the scatter plot handles
% declare an array for the handles to the scatter plots
scatterHandles = [];
Now within the for loop, delete the handles if any exist
for k = 1:1:50
% delete scatter plot data from previous iteration if it exists
if ~isempty(scatterHandles)
for m=1:length(scatterHandles)
delete(scatterHandles(m));
end
end
% get the scatter plot handles for each call to scatter
hold on
scatterHandles (1) = scatter(x1{k}(1,1), x1{k}(2,1));
scatterHandles (2) = scatter(x2{k}(1,1), x2{k}(2,1));
scatterHandles (3) = scatter(x3{k}(1,1), x3{k}(2,1));
scatterHandles (4) = scatter(x4{k}(1,1), x4{k}(2,1));
% etc.
end
Try the above and see what happens!

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