Use memmapfile with 11bit data

I am trying to use the "memmapfile" function to map a very large 11bit image to memory.

I am unclear about the Format entry in this case...

img = memmapfile(file_path, 'Format',{'???',[img_size(1) img_size(2)],'im'});

Thanks!!! Monica

Answer 1

[Walter Roberson]

memmapfile() cannot be used to map at the bit level. The closest you can get is to map by uint* and extract the bits with bitget() or the like.