operations on two different matrices

6 vues (au cours des 30 derniers jours)
Mohamed Hajjaj
Mohamed Hajjaj le 14 Sep 2021
Commenté : Mohamed Hajjaj le 16 Sep 2021
I need to replace the first row from a matrix A(m.m) by first row from another matrix B(n.n) with different size?

Réponse acceptée

Walter Roberson
Walter Roberson le 16 Sep 2021
D0 j=1,8
A(1, j)=D(2,j+1)
end do
Acol = size(A,2);
A(1,:) = D(2,2:Acol+1);
vec = DD1(1,:);
A1(idx,:) = repmat(vec,numel(idx),1);
Acol = size(A,2);
vec = DD1(1,1:Acol);
A1(idx,:) = repmat(vec, numel(idx), 1);
  1 commentaire
Mohamed Hajjaj
Mohamed Hajjaj le 16 Sep 2021
Yes, it works. Thank you very much for your help.

Connectez-vous pour commenter.

Plus de réponses (1)

the cyclist
the cyclist le 14 Sep 2021
Modifié(e) : the cyclist le 15 Sep 2021
Suppose ...
m = 3;
n = 4;
A = magic(m)
A = 3×3
8 1 6 3 5 7 4 9 2
B = magic(n)
B = 4×4
16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1
The first row of A is a 1x3 row vector, and the first row of B is a 1x4 row vector. What do you want the output to be? Also, what if m had been greater than n?
  6 commentaires
the cyclist
the cyclist le 15 Sep 2021
Sorry, but your last two comments are just confusing to me.
You did not respond to my questions. What are the results for Case 1, Case 2, etc?
I don't know Fortran anymore, so cannot interpret that.
Why are you suddenly introducing new variables (D, DD1, idx)? Your original question seemed very simple, about filling in the first row of a matrix A, from the first row of a matrix B. It seems to be getting more and more complicated with every comment.
Mohamed Hajjaj
Mohamed Hajjaj le 16 Sep 2021
The first case is the nearest one to my problem.The symbols D, DD1, ...are matrices, but I'm sorry about any confusion. Would you please help me for the first case?

Connectez-vous pour commenter.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Produits


Version

R2014b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by