Use a variable with a file extenstion to load files

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David
David le 14 Août 2014
Commenté : David le 14 Août 2014
Hi,
I Have 51 files in their own directory all of .out extention created by a seperate program, all numbered 0 to 50.
ie
0.out
1.out
2.out
and so on til 50.out.
I need to load each file 1 by one to do calculations upon them within a for loop. How would I do this using the count variable to load the file, if the directory is set beforehand?
i.e.
%set directiory
cd(......)
%for loop
For count = 0:50,
data = count.out *<-----this line*
.....
Many thanks!

Réponse acceptée

Chad Greene
Chad Greene le 14 Août 2014
You can use sprintf or num2str. num2str is easier to use, but sprintf gives many more options including leading zeros.
  2 commentaires
Chad Greene
Chad Greene le 14 Août 2014
data = load([num2str(count),'.out']);
David
David le 14 Août 2014
thanks:)

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