How to print result in MATLAB?

58 vues (au cours des 30 derniers jours)
Phan
Phan le 21 Août 2014
Commenté : Phan le 21 Août 2014
Dear everyone,
Please help me to solve this problem. I have two arrays like this:
Name=['ABC-8' 'S8' 'EG8'];
Thick=[25 16 12];
I want to create an array like this:
Z=['ABC-825' 'S816' 'EG812'];
Can anyone help me to write a code to make that array?
Thank you so much!

Réponse acceptée

Aniruddha Phatak
Aniruddha Phatak le 21 Août 2014
Robert is right, you must define it as a cell array.
name={'ABC-8' 'S8' 'EG8'};
thick=[25 16 12];
for i=1:3
thin{i} = [ num2str( thick(i) ) ];
z{i} = strcat(name{i},thin{i});
end
disp(z);

Plus de réponses (3)

David Sanchez
David Sanchez le 21 Août 2014
define your Name array as a cell, then:
Name={'ABC-8' 'S8' 'EG8'};
Thick=[25 16 12];
Z =cell(numel(Name),1);
for k=1:numel(Name)
Z{k} = strcat(Name{k},num2str(Thick(k)));
end
>> Z
Z =
'ABC-825'
'S816'
'EG812'
  1 commentaire
Phan
Phan le 21 Août 2014
Thank you so much!

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Guillaume
Guillaume le 21 Août 2014
Modifié(e) : Guillaume le 21 Août 2014
Assuming that Name is a cell array, that is
Name = {'ABC-8' 'S8' 'EG8'};
(otherwise as you wrote it, it's just a single string). Then:
Z = cellfun(@(s,n) sprintf('%s%d', s, n), Name, num2cell(Thick), 'UniformOutput', false);
will do it. Note that Z has to be a cell array.
  1 commentaire
Phan
Phan le 21 Août 2014
Thank you so much!

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Robert Cumming
Robert Cumming le 21 Août 2014
The two answers on here are correct - however if you take the for loop from one and the sprintf from the other you get a faster result:
Z =cell(1,numel(Name));
for k=1:numel(Name)
Z{k} = sprintf ( '%s%d', Name{k}, Thick(k) );
end
Speed evidence:
clear
clc
Name={'ABC-8' 'S8' 'EG8'};
Thick=[25 16 12];
tic
ZA =cell(1,numel(Name));
for k=1:numel(Name)
ZA{k} = strcat(Name{k},num2str(Thick(k)));
end
toc
tic
ZB = cellfun(@(s,n) sprintf('%s%d', s, n), Name, num2cell(Thick), 'UniformOutput', false);
toc
tic
ZC =cell(1,numel(Name));
for k=1:numel(Name)
ZC{k} = sprintf ( '%s%d', Name{k}, Thick(k) );
end
toc
isequal ( ZA, ZB )
isequal ( ZA, ZC )
Elapsed time is 0.011248 seconds.
Elapsed time is 0.011344 seconds.
Elapsed time is 0.006111 seconds.
  3 commentaires
Robert Cumming
Robert Cumming le 21 Août 2014
For this type of question you could solve it in many ways....
I just highlight this as many people overlook the simple for loop and the fact that sprintf is the fastest way for handling strings...
Phan
Phan le 21 Août 2014
Thank you all! You helped so much!

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