Append column given a 'year' condition

I have a cell type variable A with 30000 rows and 29 columns, for example:

    b1  *b2*      b3      b4      b5      b6      b7 ...     
 A={7  1999  28,14  1388  33  78  39021
    8  2002  44,44  150  4  56  60012
    12  2002  54,46  100  21  49  40701
    13  1998  46,41  189  22  44  30901...}.

Column b2 gives different years. I am trying to a ppend a new column that, for example, gives 1 if the year in b2 is after 2000 and 0 if the year in b2 is before 2000 . For instance in this example I would get:

    b1  *b2*      b3      b4      b5      b6      b7 ...  b30    
  A={7  1999  28,14  1388  33  78  39021      0
     8  2002  44,44  150  4  56  60012      1
     12  2002  54,46  100  21  49  40701      1
     13  1998  46,41  189  22  44  30901...   0}.

Can someone help me please? Thank you.

[José-Luis]

Is A a cell array?

[Maria]

yes.

Answer 1

[Guillaume]

 A(:, end+1) = num2cell([A{:, 2}] >= 2000);

[Guillaume]

However, if you only have numbers in your cell array, why aren't you using a matrix? It makes manipulation much easier

 A = cell2mat(A);
 A(:, end+1) = A(:, 2) >= 2000;

[Maria]

you are right. Thanks

Answer 2

[José-Luis]

A = num2cell(1995 + randi(10,[20 1]));
A(:,end+1) = num2cell( cell2mat(A) >= 2000)