what will be the solution for this error
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function idx=nomc(meas)
W=SimilarMatrix(meas,1);
D=diag(sum(W));
L=D-W;
Lsym=(D^(-1/2))*L*(D^(-1/2));
[ev ed]=eig(Lsym);
d=diag(ed); %#ok<NASGU>
V=ev(:,1:3);
for i=1:250
for j=1:7
U(i,j)=V(i,j)/sqrt(sum(V(i,:).^2)); %#ok<AGROW>
end
end
idx=kmeans(U,3);
figure;plot(idx);
result=[length(find(idx==1)),length(find(idx==2)),length(find(idx==3))];
getting error
??? Attempted to access V(1,4); index out of bounds because
size(V)=[143,3].
Error in ==> nomc at 11
U(i,j)=V(i,j)/sqrt(sum(V(i,:).^2)); %#ok<AGROW>
Error in ==> Normalizemeanseg at 120
f=nomc(y);
2 commentaires
Rushikesh Tade
le 12 Sep 2014
can you provide "meas" variable in mat format or provide dimensions?
Poonam
le 12 Sep 2014
Réponses (1)
Titus Edelhofer
le 12 Sep 2014
Hi,
you write
V = ev(:, 1:3);
so V has three columns. But your loop on j is
for j=1:7
That doesn't match ...
Titus
4 commentaires
Poonam
le 12 Sep 2014
Pierre Benoit
le 12 Sep 2014
Modifié(e) : Pierre Benoit
le 12 Sep 2014
Well you should check the value of i then. You should use the sizes of V for your loop boundaries rather than some magic numbers.
Type
dbstop if error
in your command window before running your code, it will be easier to understand what went wrong.
Image Analyst
le 12 Sep 2014
Poonam, I think you're mistaken. If the error says
Attempted to access V(1,4);
and your code is
for j=1:3
Then there is no way the second index of V could be 4 in this line
U(i,j)=V(i,j).....
Pierre Benoit
le 12 Sep 2014
Modifié(e) : Pierre Benoit
le 12 Sep 2014
Well, my guess was that this is no longer j that was causing a problem but i since the boundary of this loop is also quite arbitrary. And, maybe the author forgot to tell us or didn't see that the error changed a little.
But at this point, we can only guess given how little information we have.
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