store values in array in nested for loop

ss=1;
for i = 1:2
    for j = 1:5
        T = norm(r2(j,:)-r1(i,5:end)); % reading 2 excel files and r2 and r1 are rows
          RS(ss) = T
          ss = ss + 1;
    end
    [r,c]=min(RS)
  clearvars RS
end
end

As i run the code I got this result after 1 iteration

RS =
 613.3480  566.6174  614.9722  644.0272  627.2652

r =

566.6174

c =

     2

but as i=2 it displays

RS =

           0         0         0         0         0  602.8387  522.1276  605.9619  535.2905  468.5696

r =

     0

c =

     1

I want to know the min value from RS at each iteration and i want to have

RS = 
  602.8387  522.1276  605.9619  535.2905  468.5696

with no zeros in my array,so that i get the correct min value. Thankx

[per isakson]

What values do r1 and r2 have?

Answer 1

[Roger Stafford]

To get the correct minimum values, replace "clearvars RS" with "ss=1;".

If you want to retain a record of these two minimums and their indices, you need to store them in arrays at the end of each of the two passes in the outer for-loop.

[Muhammad Usman]

Thankyou so much, i am very grateful for you. your solution works for me

Answer 2

[Andrei Bobrov]

[r,c] = min(squeeze(sqrt(...
            sum(bsxfun(@minus,r2(1:5,:),permute(r1(1:2,5:end),[3 2 1])).^2,2))));