MAKING SUBJECT OF FOMULAR
9 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
HOW DO I MAKE X SUBJECT OF FOMULAR IN THIS EQUATION x = exp(x+y).
I have tried the following code
syms x y
solve('x = exp(x+y)',x)
and this give me *
[sym empty].*
How best can I do it.
1 commentaire
Chibuzo Chukwu
le 13 Déc 2018
I am also stoked with a situation of the same form. All out gigs should please look into this kind of problem and suggest a way out.
Réponses (2)
Walter Roberson
le 13 Déc 2018
In older versions of MATLAB,
solve('x = exp(x+y)', 'x')
In more modern versions
syms x y
solve(x == exp(x+y), x)
However, MATLAB is not able to find a solution. A solution exists, and is
-lambertw(-exp(y))
but MATLAB is not strong on Lambert W processing.
1 commentaire
Chibuzo Chukwu
le 13 Déc 2018
Thanks for your response. I have tried to read about the Lambert W function and it has been helpful but can you look at this problem?
There are series of values for x and a and it's required to have a linear plot of a against x in the equation connecting them
ln(x^alpha * a) = c- 2*x*m
To determine values alpha and m from the graph
Is there anyway this can be rearrange to achieve this?
15 commentaires
Walter Roberson
le 17 Déc 2018
No. If part of your data has a linear fit then it makes no sense to fit a power model to it.
If you want a linear fit then set alpha to 0. That would get ln a on the left side and linear terms on the right leading to aa simple polynomial fit.
Chibuzo Chukwu
le 17 Déc 2018
Thanks a lot. Your insight has been very useful and infact you've answered my question very satisfactory. I will get back to you if I find any other obstacle. Thanks a million.
Voir également
Catégories
En savoir plus sur Linear Algebra dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!